問題描述

如題，如能有具體示例或demo鏈接感激不盡

問題解答

var userId = 1, name = ’test’;var query = connection.query(’SELECT * FROM users WHERE id = ’ + connection.escape(userId) + ’, name = ’ + connection.escape(name), function(err, results) { // ...});console.log(query.sql); // SELECT * FROM users WHERE id = 1, name = ’test’使用connection.query()的查詢參數占位符

var userId = 1, name = ’test’;var query = connection.query(’SELECT * FROM users WHERE id = ?, name = ?’, [userId, name], function(err, results) { // ...});console.log(query.sql); // SELECT * FROM users WHERE id = 1, name = ’test’使用escapeId()編碼SQL查詢標識符

var sorter = ’date’;var sql = ’SELECT * FROM posts ORDER BY ’ + connection.escapeId(sorter);connection.query(sql, function(err, results) { // ...});使用mysql.format()轉義參數

var userId = 1;var sql = 'SELECT * FROM ?? WHERE ?? = ?';var inserts = [’users’, ’id’, userId];sql = mysql.format(sql, inserts); // SELECT * FROM users WHERE id = 1

Ref: http://www.dengzhr.com/node-j...

PS: Google第一頁就是答案