問題描述

<?php$arr=array( '教學(xué)部'=>array( array('李1','18','人妖'), array('高1','20','男'), array('張1','21','妖人'), ), '宣傳部'=>array( array('李2','18','人妖'), array('高2','20','男'), array('張2','21','妖人'), ), '財(cái)務(wù)部'=>array( array('李3','18','人妖'), array('高3','20','男'), array('張某','21','妖人'), ),);foreach($arr as $k=>$a){echo'<table width="500" border="1">';echo $k ; foreach($a as $b=>$c){ foreach($c as $d=>$e){ $i=list($one,$two,$three)=$e; { echo '<td>'.$i.'</td>'; } } } echo '</table>'; } ?>

問題解答

輸出應(yīng)該是這個(gè)樣式

foreach($arr as $k=>$a){ echo''; echo $k ; foreach($a as $b=>$c){ echo "<tr>"; foreach($c as $d=>$e){ $i=list($one,$two,$three)=$e; echo ''.$i.''; echo "</tr>"; } } echo ''; }

在第一層foreach內(nèi)部的開始和結(jié)束分別添加

與即可